rust/src/libcore/default.rs
Alex Crichton 626e754473 Bump version, upgrade bootstrap
This commit updates the version number to 1.17.0 as we're not on that version of
the nightly compiler, and at the same time this updates src/stage0.txt to
bootstrap from freshly minted beta compiler and beta Cargo.
2017-02-03 13:25:46 -08:00

158 lines
3.8 KiB
Rust

// Copyright 2013 The Rust Project Developers. See the COPYRIGHT
// file at the top-level directory of this distribution and at
// http://rust-lang.org/COPYRIGHT.
//
// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
// option. This file may not be copied, modified, or distributed
// except according to those terms.
//! The `Default` trait for types which may have meaningful default values.
#![stable(feature = "rust1", since = "1.0.0")]
/// A trait for giving a type a useful default value.
///
/// Sometimes, you want to fall back to some kind of default value, and
/// don't particularly care what it is. This comes up often with `struct`s
/// that define a set of options:
///
/// ```
/// # #[allow(dead_code)]
/// struct SomeOptions {
/// foo: i32,
/// bar: f32,
/// }
/// ```
///
/// How can we define some default values? You can use `Default`:
///
/// ```
/// # #[allow(dead_code)]
/// #[derive(Default)]
/// struct SomeOptions {
/// foo: i32,
/// bar: f32,
/// }
///
/// fn main() {
/// let options: SomeOptions = Default::default();
/// }
/// ```
///
/// Now, you get all of the default values. Rust implements `Default` for various primitives types.
///
/// If you want to override a particular option, but still retain the other defaults:
///
/// ```
/// # #[allow(dead_code)]
/// # #[derive(Default)]
/// # struct SomeOptions {
/// # foo: i32,
/// # bar: f32,
/// # }
/// fn main() {
/// let options = SomeOptions { foo: 42, ..Default::default() };
/// }
/// ```
///
/// ## Derivable
///
/// This trait can be used with `#[derive]` if all of the type's fields implement
/// `Default`. When `derive`d, it will use the default value for each field's type.
///
/// ## How can I implement `Default`?
///
/// Provide an implementation for the `default()` method that returns the value of
/// your type that should be the default:
///
/// ```
/// # #![allow(dead_code)]
/// enum Kind {
/// A,
/// B,
/// C,
/// }
///
/// impl Default for Kind {
/// fn default() -> Kind { Kind::A }
/// }
/// ```
///
/// # Examples
///
/// ```
/// # #[allow(dead_code)]
/// #[derive(Default)]
/// struct SomeOptions {
/// foo: i32,
/// bar: f32,
/// }
/// ```
#[stable(feature = "rust1", since = "1.0.0")]
pub trait Default: Sized {
/// Returns the "default value" for a type.
///
/// Default values are often some kind of initial value, identity value, or anything else that
/// may make sense as a default.
///
/// # Examples
///
/// Using built-in default values:
///
/// ```
/// let i: i8 = Default::default();
/// let (x, y): (Option<String>, f64) = Default::default();
/// let (a, b, (c, d)): (i32, u32, (bool, bool)) = Default::default();
/// ```
///
/// Making your own:
///
/// ```
/// # #[allow(dead_code)]
/// enum Kind {
/// A,
/// B,
/// C,
/// }
///
/// impl Default for Kind {
/// fn default() -> Kind { Kind::A }
/// }
/// ```
#[stable(feature = "rust1", since = "1.0.0")]
fn default() -> Self;
}
macro_rules! default_impl {
($t:ty, $v:expr) => {
#[stable(feature = "rust1", since = "1.0.0")]
impl Default for $t {
#[inline]
fn default() -> $t { $v }
}
}
}
default_impl! { (), () }
default_impl! { bool, false }
default_impl! { char, '\x00' }
default_impl! { usize, 0 }
default_impl! { u8, 0 }
default_impl! { u16, 0 }
default_impl! { u32, 0 }
default_impl! { u64, 0 }
default_impl! { u128, 0 }
default_impl! { isize, 0 }
default_impl! { i8, 0 }
default_impl! { i16, 0 }
default_impl! { i32, 0 }
default_impl! { i64, 0 }
default_impl! { i128, 0 }
default_impl! { f32, 0.0f32 }
default_impl! { f64, 0.0f64 }