2015-01-08 12:27:03 -06:00
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% Functions
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2014-12-02 08:20:48 -06:00
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You've already seen one function so far, the `main` function:
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2015-02-13 09:05:33 -06:00
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```rust
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2014-12-02 08:20:48 -06:00
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fn main() {
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}
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```
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This is the simplest possible function declaration. As we mentioned before,
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2015-01-08 18:52:50 -06:00
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`fn` says "this is a function," followed by the name, some parentheses because
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2014-12-02 08:20:48 -06:00
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this function takes no arguments, and then some curly braces to indicate the
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body. Here's a function named `foo`:
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2015-02-13 09:05:33 -06:00
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```rust
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2014-12-02 08:20:48 -06:00
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fn foo() {
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}
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```
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So, what about taking arguments? Here's a function that prints a number:
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2015-02-13 09:05:33 -06:00
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```rust
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2014-12-02 08:20:48 -06:00
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fn print_number(x: i32) {
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println!("x is: {}", x);
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}
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```
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Here's a complete program that uses `print_number`:
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2015-02-13 09:05:33 -06:00
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```rust
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2014-12-02 08:20:48 -06:00
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fn main() {
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print_number(5);
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}
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fn print_number(x: i32) {
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println!("x is: {}", x);
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}
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```
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As you can see, function arguments work very similar to `let` declarations:
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you add a type to the argument name, after a colon.
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Here's a complete program that adds two numbers together and prints them:
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2015-02-13 09:05:33 -06:00
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```rust
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2014-12-02 08:20:48 -06:00
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fn main() {
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print_sum(5, 6);
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}
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fn print_sum(x: i32, y: i32) {
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println!("sum is: {}", x + y);
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}
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```
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You separate arguments with a comma, both when you call the function, as well
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as when you declare it.
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Unlike `let`, you _must_ declare the types of function arguments. This does
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not work:
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2015-02-13 09:05:33 -06:00
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```{rust,ignore}
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2015-01-10 16:10:00 -06:00
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fn print_sum(x, y) {
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2015-02-13 11:09:46 -06:00
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println!("sum is: {}", x + y);
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2014-12-02 08:20:48 -06:00
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}
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```
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You get this error:
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```text
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2015-01-10 16:10:00 -06:00
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hello.rs:5:18: 5:19 expected one of `!`, `:`, or `@`, found `)`
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hello.rs:5 fn print_number(x, y) {
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```
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This is a deliberate design decision. While full-program inference is possible,
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languages which have it, like Haskell, often suggest that documenting your
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types explicitly is a best-practice. We agree that forcing functions to declare
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types while allowing for inference inside of function bodies is a wonderful
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sweet spot between full inference and no inference.
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What about returning a value? Here's a function that adds one to an integer:
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2015-02-13 09:05:33 -06:00
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```rust
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2014-12-02 08:20:48 -06:00
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fn add_one(x: i32) -> i32 {
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x + 1
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}
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```
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Rust functions return exactly one value, and you declare the type after an
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2015-01-08 18:52:50 -06:00
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"arrow," which is a dash (`-`) followed by a greater-than sign (`>`).
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2014-12-02 08:20:48 -06:00
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You'll note the lack of a semicolon here. If we added it in:
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2015-02-13 09:05:33 -06:00
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```{rust,ignore}
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2014-12-02 08:20:48 -06:00
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fn add_one(x: i32) -> i32 {
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x + 1;
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}
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```
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We would get an error:
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```text
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error: not all control paths return a value
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fn add_one(x: i32) -> i32 {
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x + 1;
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}
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help: consider removing this semicolon:
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x + 1;
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^
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```
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Remember our earlier discussions about semicolons and `()`? Our function claims
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to return an `i32`, but with a semicolon, it would return `()` instead. Rust
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realizes this probably isn't what we want, and suggests removing the semicolon.
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This is very much like our `if` statement before: the result of the block
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(`{}`) is the value of the expression. Other expression-oriented languages,
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such as Ruby, work like this, but it's a bit unusual in the systems programming
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world. When people first learn about this, they usually assume that it
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introduces bugs. But because Rust's type system is so strong, and because unit
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is its own unique type, we have never seen an issue where adding or removing a
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semicolon in a return position would cause a bug.
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But what about early returns? Rust does have a keyword for that, `return`:
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2015-02-13 09:05:33 -06:00
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```rust
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2014-12-02 08:20:48 -06:00
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fn foo(x: i32) -> i32 {
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if x < 5 { return x; }
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x + 1
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}
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```
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Using a `return` as the last line of a function works, but is considered poor
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style:
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2015-02-13 09:05:33 -06:00
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```rust
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2014-12-02 08:20:48 -06:00
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fn foo(x: i32) -> i32 {
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if x < 5 { return x; }
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return x + 1;
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}
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```
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2015-01-15 13:47:21 -06:00
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The previous definition without `return` may look a bit strange if you haven't
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2015-01-16 12:08:08 -06:00
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worked in an expression-based language before, but it becomes intuitive over
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2015-01-15 13:47:21 -06:00
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time. If this were production code, we wouldn't write it in that way anyway,
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we'd write this:
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```rust
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fn foo(x: i32) -> i32 {
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if x < 5 {
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x
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} else {
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x + 1
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}
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}
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```
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Because `if` is an expression, and it's the only expression in this function,
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the value will be the result of the `if`.
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2015-02-13 09:05:33 -06:00
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## Diverging functions
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Rust has some special syntax for 'diverging functions', which are functions that
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do not return:
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```
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fn diverges() -> ! {
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panic!("This function never returns!");
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}
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```
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`panic!` is a macro, similar to `println!()` that we've already seen. Unlike
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`println!()`, `panic!()` causes the current thread of execution to crash with
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the given message.
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Because this function will cause a crash, it will never return, and so it has
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the type '`!`', which is read "diverges." A diverging function can be used
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as any type:
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```should_fail
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# fn diverges() -> ! {
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# panic!("This function never returns!");
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# }
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let x: i32 = diverges();
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let x: String = diverges();
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```
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We don't have a good use for diverging functions yet, because they're used in
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conjunction with other Rust features. But when you see `-> !` later, you'll
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know what it's called.
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