Clarify function return style.
Suggested here: http://stackoverflow.com/a/27962076/24817
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@ -142,5 +142,23 @@ fn foo(x: i32) -> i32 {
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}
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```
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The previous definition without `return` may look a bit strange if you haven't
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worked in an expression-based language before, but it becomes intutive over
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time. If this were production code, we wouldn't write it in that way anyway,
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we'd write this:
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```rust
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fn foo(x: i32) -> i32 {
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if x < 5 {
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x
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} else {
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x + 1
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}
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}
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```
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Because `if` is an expression, and it's the only expression in this function,
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the value will be the result of the `if`.
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There are some additional ways to define functions, but they involve features
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that we haven't learned about yet, so let's just leave it at that for now.
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