rust/src/test/run-pass/extern-pass-u64.rs
Alex Crichton 9fbba7b2ee Statically link librustrt to libstd
This commit alters the build process of the compiler to build a static
librustrt.a instead of a dynamic version. This means that we can stop
distributing librustrt as well as default linking against it in the compiler.

This also means that if you attempt to build rust code without libstd, it will
no longer work if there are any landing pads in play. The reason for this is
that LLVM and rustc will emit calls to the various upcalls in librustrt used to
manage exception handling. In theory we could split librustrt into librustrt and
librustupcall. We would then distribute librustupcall and link to it for all
programs using landing pads, but I would rather see just one librustrt artifact
and simplify the build process.

The major benefit of doing this is that building a static rust library for use
in embedded situations all of a sudden just became a whole lot more feasible.

Closes #3361
2013-11-29 18:36:14 -08:00

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Rust

// Copyright 2012 The Rust Project Developers. See the COPYRIGHT
// file at the top-level directory of this distribution and at
// http://rust-lang.org/COPYRIGHT.
//
// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
// option. This file may not be copied, modified, or distributed
// except according to those terms.
// Test a call to a function that takes/returns a u64.
#[link(name = "rustrt")]
extern {
pub fn rust_dbg_extern_identity_u64(v: u64) -> u64;
}
pub fn main() {
unsafe {
assert_eq!(22_u64, rust_dbg_extern_identity_u64(22_u64));
}
}