rust/src/test/run-pass/deriving-zero.rs
Erick Tryzelaar f107718a9b std: Remove Zero impl for Option
Options are not numeric types, so it doesn't make sense for them to
implement Zero.
2013-09-12 18:54:13 -07:00

40 lines
911 B
Rust

// Copyright 2012-2013 The Rust Project Developers. See the COPYRIGHT
// file at the top-level directory of this distribution and at
// http://rust-lang.org/COPYRIGHT.
//
// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
// option. This file may not be copied, modified, or distributed
// except according to those terms.
use std::util;
use std::num::Zero;
#[deriving(Zero)]
struct A;
#[deriving(Zero)]
struct B(int);
#[deriving(Zero)]
struct C(int, int);
#[deriving(Zero)]
struct D { a: int }
#[deriving(Zero)]
struct E { a: int, b: int }
#[deriving(Zero)]
struct Lots {
d: u8,
e: char,
f: float,
g: (f32, char),
h: @mut (int, int),
i: bool,
j: (),
}
fn main() {
let lots: Lots = Zero::zero();
assert!(lots.is_zero());
}