d1dcd19d26
This breaks code like:
struct A<'a> {
func: &'a fn() -> Option<int>
}
fn foo() -> Option<int> { ... }
fn create() -> A<'static> {
A {
func: &foo
}
}
Change this code to not take functions by reference. For example:
struct A {
func: extern "Rust" fn() -> Option<int>
}
fn foo() -> Option<int> { ... }
fn create() -> A {
A {
func: foo
}
}
Closes #13595.
[breaking-change]
35 lines
808 B
Rust
35 lines
808 B
Rust
// Copyright 2014 The Rust Project Developers. See the COPYRIGHT
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// file at the top-level directory of this distribution and at
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// http://rust-lang.org/COPYRIGHT.
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//
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// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
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// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
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// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
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// option. This file may not be copied, modified, or distributed
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// except according to those terms.
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struct A<'a> {
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func: &'a fn() -> Option<int>
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}
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impl<'a> A<'a> {
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fn call(&self) -> Option<int> {
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(*self.func)()
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}
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}
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fn foo() -> Option<int> {
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None
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}
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fn create() -> A<'static> {
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A {
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func: &foo, //~ ERROR borrowed value does not live long enough
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}
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}
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fn main() {
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let a = create();
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a.call();
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}
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