9323a0d1be
Parse `Ty?` as `Option<Ty>` and provide structured suggestion Swift has specific syntax that desugars to `Option<T>` similar to our `?` operator, which means that people might try to use it in Rust. Parse it and gracefully recover. |
||
---|---|---|
.. | ||
lexer | ||
parser | ||
lib.rs | ||
validate_attr.rs |