rust/src/test/run-pass/issue-9394-inherited-trait-calls.rs
Branimir a4b7474461 Fix ICE caused by my previous patch, that is, if super trait had more
methods tnan subtrait, compiling would fail. I simply forgot to update
variable name. Updated test case , too.
2013-09-26 16:59:54 +02:00

71 lines
1.4 KiB
Rust

// Copyright 2012 The Rust Project Developers. See the COPYRIGHT
// file at the top-level directory of this distribution and at
// http://rust-lang.org/COPYRIGHT.
//
// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
// option. This file may not be copied, modified, or distributed
// except according to those terms.
trait Base: Base2 + Base3{
fn foo(&self) -> ~str;
fn foo1(&self) -> ~str;
fn foo2(&self) -> ~str{
~"base foo2"
}
}
trait Base2: Base3{
fn baz(&self) -> ~str;
}
trait Base3{
fn root(&self) -> ~str;
}
trait Super: Base{
fn bar(&self) -> ~str;
}
struct X;
impl Base for X {
fn foo(&self) -> ~str{
~"base foo"
}
fn foo1(&self) -> ~str{
~"base foo1"
}
}
impl Base2 for X {
fn baz(&self) -> ~str{
~"base2 baz"
}
}
impl Base3 for X {
fn root(&self) -> ~str{
~"base3 root"
}
}
impl Super for X {
fn bar(&self) -> ~str{
~"super bar"
}
}
pub fn main() {
let n = X;
let s = &n as &Super;
assert_eq!(s.bar(),~"super bar");
assert_eq!(s.foo(),~"base foo");
assert_eq!(s.foo1(),~"base foo1");
assert_eq!(s.foo2(),~"base foo2");
assert_eq!(s.baz(),~"base2 baz");
assert_eq!(s.root(),~"base3 root");
}