rust/tests/ui/nll/ty-outlives/ty-param-closure-outlives-from-where-clause.rs
2023-01-11 09:32:08 +00:00

83 lines
2.1 KiB
Rust

// Test that we can propagate `T: 'a` obligations to our caller. See
// `correct_region` for an explanation of how this test is setup; it's
// somewhat intricate.
// compile-flags:-Zverbose
#![allow(warnings)]
#![feature(rustc_attrs)]
use std::cell::Cell;
fn with_signature<'a, T, F>(a: Cell<&'a ()>, b: T, op: F)
where
F: FnOnce(Cell<&'a ()>, T),
{
op(a, b)
}
fn require<'a, T>(_a: &Cell<&'a ()>, _b: &T)
where
T: 'a,
{
}
#[rustc_regions]
fn no_region<'a, T>(a: Cell<&'a ()>, b: T) {
with_signature(a, b, |x, y| {
// See `correct_region`, which explains the point of this
// test. The only difference is that, in the case of this
// function, there is no where clause *anywhere*, and hence we
// get an error (but reported by the closure creator).
require(&x, &y)
//~^ ERROR the parameter type `T` may not live long enough
})
}
#[rustc_regions]
fn correct_region<'a, T>(a: Cell<&'a ()>, b: T)
where
T: 'a,
{
with_signature(a, b, |x, y| {
// Key point of this test:
//
// The *closure* is being type-checked with all of its free
// regions "universalized". In particular, it does not know
// that `x` has the type `Cell<&'a ()>`, but rather treats it
// as if the type of `x` is `Cell<&'A ()>`, where `'A` is some
// fresh, independent region distinct from the `'a` which
// appears in the environment. The call to `require` here
// forces us then to prove that `T: 'A`, but the closure
// cannot do it on its own. It has to surface this requirement
// to its creator (which knows that `'a == 'A`).
require(&x, &y)
})
}
#[rustc_regions]
fn wrong_region<'a, 'b, T>(a: Cell<&'a ()>, b: T)
where
T: 'b,
{
with_signature(a, b, |x, y| {
// See `correct_region`
require(&x, &y)
//~^ ERROR the parameter type `T` may not live long enough
})
}
#[rustc_regions]
fn outlives_region<'a, 'b, T>(a: Cell<&'a ()>, b: T)
where
T: 'b,
'b: 'a,
{
with_signature(a, b, |x, y| {
// See `correct_region`
require(&x, &y)
})
}
fn main() {}