rust/src/librustc_privacy/diagnostics.rs

// Copyright 2014 The Rust Project Developers. See the COPYRIGHT
// file at the top-level directory of this distribution and at
// http://rust-lang.org/COPYRIGHT.
//
// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
// option. This file may not be copied, modified, or distributed
// except according to those terms.

#![allow(non_snake_case)]

register_long_diagnostics! {

E0445: r##"
A private trait was used on a public type parameter bound. Erroneous code
examples:

```compile_fail,E0445
#![deny(private_in_public)]

trait Foo {
    fn dummy(&self) { }
}

pub trait Bar : Foo {} // error: private trait in public interface
pub struct Bar2<T: Foo>(pub T); // same error
pub fn foo<T: Foo> (t: T) {} // same error
```

To solve this error, please ensure that the trait is also public. The trait
can be made inaccessible if necessary by placing it into a private inner
module, but it still has to be marked with `pub`. Example:

```
pub trait Foo { // we set the Foo trait public
    fn dummy(&self) { }
}

pub trait Bar : Foo {} // ok!
pub struct Bar2<T: Foo>(pub T); // ok!
pub fn foo<T: Foo> (t: T) {} // ok!
```
"##,

E0446: r##"
A private type was used in a public type signature. Erroneous code example:

```compile_fail,E0446
#![deny(private_in_public)]

mod Foo {
    struct Bar(u32);

    pub fn bar() -> Bar { // error: private type in public interface
        Bar(0)
    }
}
```

To solve this error, please ensure that the type is also public. The type
can be made inaccessible if necessary by placing it into a private inner
module, but it still has to be marked with `pub`.
Example:

```
mod Foo {
    pub struct Bar(u32); // we set the Bar type public

    pub fn bar() -> Bar { // ok!
        Bar(0)
    }
}
```
"##,

E0447: r##"
#### Note: this error code is no longer emitted by the compiler.

The `pub` keyword was used inside a function. Erroneous code example:

```
fn foo() {
    pub struct Bar; // error: visibility has no effect inside functions
}
```

Since we cannot access items defined inside a function, the visibility of its
items does not impact outer code. So using the `pub` keyword in this context
is invalid.
"##,

E0448: r##"
The `pub` keyword was used inside a public enum. Erroneous code example:

```compile_fail
pub enum Foo {
    pub Bar, // error: unnecessary `pub` visibility
}
```

Since the enum is already public, adding `pub` on one its elements is
unnecessary. Example:

```compile_fail
enum Foo {
    pub Bar, // not ok!
}
```

This is the correct syntax:

```
pub enum Foo {
    Bar, // ok!
}
```
"##,

E0451: r##"
A struct constructor with private fields was invoked. Erroneous code example:

```compile_fail,E0451
mod Bar {
    pub struct Foo {
        pub a: isize,
        b: isize,
    }
}

let f = Bar::Foo{ a: 0, b: 0 }; // error: field `b` of struct `Bar::Foo`
                                //        is private
```

To fix this error, please ensure that all the fields of the struct are public,
or implement a function for easy instantiation. Examples:

```
mod Bar {
    pub struct Foo {
        pub a: isize,
        pub b: isize, // we set `b` field public
    }
}

let f = Bar::Foo{ a: 0, b: 0 }; // ok!
```

Or:

```
mod Bar {
    pub struct Foo {
        pub a: isize,
        b: isize, // still private
    }

    impl Foo {
        pub fn new() -> Foo { // we create a method to instantiate `Foo`
            Foo { a: 0, b: 0 }
        }
    }
}

let f = Bar::Foo::new(); // ok!
```
"##,

}

register_diagnostics! {
//  E0450, moved into resolve
}