error[E0597]: `y` does not live long enough
  --> $DIR/issue-23338-locals-die-before-temps-of-body.rs:10:5
   |
LL |     y.borrow().clone()
   |     ^---------
   |     |
   |     borrowed value does not live long enough
   |     a temporary with access to the borrow is created here ...
LL | }
   | -
   | |
   | `y` dropped here while still borrowed
   | ... and the borrow might be used here, when that temporary is dropped and runs the destructor for type `Ref<'_, String>`
   |
   = note: the temporary is part of an expression at the end of a block;
           consider forcing this temporary to be dropped sooner, before the block's local variables are dropped
help: for example, you could save the expression's value in a new local variable `x` and then make `x` be the expression at the end of the block
   |
LL |     let x = y.borrow().clone(); x
   |     ^^^^^^^                   ^^^

error[E0597]: `y` does not live long enough
  --> $DIR/issue-23338-locals-die-before-temps-of-body.rs:17:9
   |
LL |         y.borrow().clone()
   |         ^---------
   |         |
   |         borrowed value does not live long enough
   |         a temporary with access to the borrow is created here ...
LL |     };
   |     -- ... and the borrow might be used here, when that temporary is dropped and runs the destructor for type `Ref<'_, String>`
   |     |
   |     `y` dropped here while still borrowed
   |
   = note: the temporary is part of an expression at the end of a block;
           consider forcing this temporary to be dropped sooner, before the block's local variables are dropped
help: for example, you could save the expression's value in a new local variable `x` and then make `x` be the expression at the end of the block
   |
LL |         let x = y.borrow().clone(); x
   |         ^^^^^^^                   ^^^

error: aborting due to 2 previous errors

For more information about this error, try `rustc --explain E0597`.