//! When specifying SSR rule, you generally want to map one *kind* of thing to //! the same kind of thing: path to path, expression to expression, type to //! type. //! //! The problem is, while this *kind* is generally obvious to the human, the ide //! needs to determine it somehow. We do this in a stupid way -- by pasting SSR //! rule into different contexts and checking what works. use syntax::{ast, AstNode, SyntaxNode}; pub(crate) fn ty(s: &str) -> Result { fragment::("type T = {};", s) } pub(crate) fn item(s: &str) -> Result { fragment::("{}", s) } pub(crate) fn pat(s: &str) -> Result { fragment::("const _: () = {let {} = ();};", s) } pub(crate) fn expr(s: &str) -> Result { fragment::("const _: () = {};", s) } pub(crate) fn stmt(s: &str) -> Result { let template = "const _: () = { {}; };"; let input = template.replace("{}", s); let parse = syntax::SourceFile::parse(&input, syntax::Edition::CURRENT); if !parse.errors().is_empty() { return Err(()); } let mut node = parse.tree().syntax().descendants().skip(2).find_map(ast::Stmt::cast).ok_or(())?; if !s.ends_with(';') && node.to_string().ends_with(';') { node = node.clone_for_update(); if let Some(it) = node.syntax().last_token() { it.detach() } } if node.to_string() != s { return Err(()); } Ok(node.syntax().clone_subtree()) } fn fragment(template: &str, s: &str) -> Result { let s = s.trim(); let input = template.replace("{}", s); let parse = syntax::SourceFile::parse(&input, syntax::Edition::CURRENT); if !parse.errors().is_empty() { return Err(()); } let node = parse.tree().syntax().descendants().find_map(T::cast).ok_or(())?; if node.syntax().text() != s { return Err(()); } Ok(node.syntax().clone_subtree()) }