Rollup merge of #30727 - tbu-:pr_doc_escaped_newline, r=steveklabnik
Rust differs in that behavior from C: In C, the newline escapes are resolved before anything else, and in Rust this depends on whether the backslash is escaped itself. A difference can be observed in the following two programs: ```c int main() { printf("\\ n\n"); return 0; } ``` ```rust fn main() { println!("\\ n"); } ``` The first program prints two newlines, the second one prints a backslash, a newline, the latin character n and a final newline.
This commit is contained in:
commit
fcb1ccf8c0
@ -208,10 +208,10 @@ A _string literal_ is a sequence of any Unicode characters enclosed within two
|
||||
which must be _escaped_ by a preceding `U+005C` character (`\`).
|
||||
|
||||
Line-break characters are allowed in string literals. Normally they represent
|
||||
themselves (i.e. no translation), but as a special exception, when a `U+005C`
|
||||
character (`\`) occurs immediately before the newline, the `U+005C` character,
|
||||
the newline, and all whitespace at the beginning of the next line are ignored.
|
||||
Thus `a` and `b` are equal:
|
||||
themselves (i.e. no translation), but as a special exception, when an unescaped
|
||||
`U+005C` character (`\`) occurs immediately before the newline (`U+000A`), the
|
||||
`U+005C` character, the newline, and all whitespace at the beginning of the
|
||||
next line are ignored. Thus `a` and `b` are equal:
|
||||
|
||||
```rust
|
||||
let a = "foobar";
|
||||
|
Loading…
Reference in New Issue
Block a user