Use Niko's wording
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@ -63,14 +63,25 @@
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//! T` obtained from `Box::<T>::into_raw` may be deallocated using the
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//! [`Global`] allocator with `Layout::for_value(&*value)`.
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//!
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//! `Box<T>` has the same ABI as `&mut T`. In particular, when `T: Sized`,
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//! this allows using `Box<T>` in FFI:
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//! So long as `T: Sized`, a `Box<T>` is guaranteed to be represented as a
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//! single pointer and is also ABI-compatible with C pointers (i.e. the C type
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//! `T*`). This means that you have Rust code which passes ownership of a
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//! `Box<T>` to C code by using `Box<T>` as the type on the Rust side, and
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//! `T*` as the corresponding type on the C side. As an example, consider this
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//! C header which declares functions that create and destroy some kind of
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//! `Foo` value:
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//!
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//! ```c
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//! /* C header */
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//! struct Foo* foo_new(void); /* Returns ownership to the caller */
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//! void foo_delete(struct Foo*); /* Takes ownership from the caller */
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//! ```
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//!
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//! These two functions might be implemented in Rust as follows. Here, the
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//! `struct Foo*` type from C is translated to `Box<Foo>`, which captures
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//! the ownership constraints. Note also that the nullable argument to
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//! `foo_delete` is represented in Rust as `Option<Box<Foo>>`, since `Box<Foo>`
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//! cannot be null.
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//!
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//! ```
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//! #[repr(C)]
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@ -84,6 +95,14 @@
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//! #[no_mangle]
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//! pub extern "C" fn foo_delete(_: Option<Box<Foo>>) {}
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//! ```
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//!
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//! Even though `Box<T>` has the same representation and C ABI as a C pointer,
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//! this does not mean that you can convert an arbitrary `T*` into a `Box<T>`
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//! and expect things to work. `Box<T>` values will always be fully aligned,
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//! non-null pointers. Moreover, the destructor for `Box<T>` will attempt to
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//! free the value with the global allocator. In general, the best practice
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//! is to only use `Box<T>` for pointers that originated from the global
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//! allocator.
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//!
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//! [dereferencing]: ../../std/ops/trait.Deref.html
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//! [`Box`]: struct.Box.html
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