allocate before calling T::default in <Box<T>>::default()
The `Box<T: Default>` impl currently calls `T::default()` before allocating the `Box`. Most `Default` impls are trivial, which should in theory allow LLVM to construct `T: Default` directly in the `Box` allocation when calling `<Box<T>>::default()`. However, the allocation may fail, which necessitates calling `T's` destructor if it has one. If the destructor is non-trivial, then LLVM has a hard time proving that it's sound to elide, which makes it construct `T` on the stack first, and then copy it into the allocation. Create an uninit `Box` first, and then write `T::default` into it, so that LLVM now only needs to prove that the `T::default` can't panic, which should be trivial for most `Default` impls.
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@ -1688,7 +1688,7 @@ impl<T: Default> Default for Box<T> {
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/// Creates a `Box<T>`, with the `Default` value for T.
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#[inline]
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fn default() -> Self {
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Box::new(T::default())
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Box::write(Box::new_uninit(), T::default())
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}
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}
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@ -9,9 +9,9 @@
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// CHECK-LABEL: @box_default_inplace
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#[no_mangle]
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pub fn box_default_inplace() -> Box<(String, String)> {
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// CHECK: [[ALLOCA:%.*]] = alloca
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// CHECK-NOT: alloca
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// CHECK: [[BOX:%.*]] = {{.*}}call {{.*}}__rust_alloc(
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// CHECK: call void @llvm.memcpy{{.*}}(ptr {{.*}}[[BOX]], ptr {{.*}}[[ALLOCA]]
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// CHECK-NOT: call void @llvm.memcpy
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// CHECK: ret ptr [[BOX]]
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Box::default()
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}
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