fix weak memory bug in TLS on Windows
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c8d19a92aa
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d5d714bb34
@ -141,9 +141,15 @@ unsafe fn init(&'static self) -> Key {
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panic!("out of TLS indexes");
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}
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self.key.store(key + 1, Release);
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register_dtor(self);
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// Release-storing the key needs to be the last thing we do.
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// This is because in `fn key()`, other threads will do an acquire load of the key,
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// and if that sees this write then it will entirely bypass the `InitOnce`. We thus
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// need to establish synchronization through `key`. In particular that acquire load
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// must happen-after the register_dtor above, to ensure the dtor actually runs!
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self.key.store(key + 1, Release);
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let r = c::InitOnceComplete(self.once.get(), 0, ptr::null_mut());
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debug_assert_eq!(r, c::TRUE);
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@ -313,8 +319,22 @@ unsafe fn run_dtors() {
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// Use acquire ordering to observe key initialization.
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let mut cur = DTORS.load(Acquire);
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while !cur.is_null() {
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let key = (*cur).key.load(Relaxed) - 1;
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let pre_key = (*cur).key.load(Acquire);
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let dtor = (*cur).dtor.unwrap();
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cur = (*cur).next.load(Relaxed);
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// In StaticKey::init, we register the dtor before setting `key`.
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// So if one thread's `run_dtors` races with another thread executing `init` on the same
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// `StaticKey`, we can encounter a key of 0 here. That means this key was never
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// initialized in this thread so we can safely skip it.
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if pre_key == 0 {
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continue;
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}
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// If this is non-zero, then via the `Acquire` load above we synchronized with
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// everything relevant for this key. (It's not clear that this is needed, since the
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// release-acquire pair on DTORS also establishes synchronization, but better safe than
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// sorry.)
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let key = pre_key - 1;
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let ptr = c::TlsGetValue(key);
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if !ptr.is_null() {
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@ -322,8 +342,6 @@ unsafe fn run_dtors() {
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dtor(ptr as *mut _);
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any_run = true;
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}
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cur = (*cur).next.load(Relaxed);
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}
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if !any_run {
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