Remove a debug! statement before I/O is ready
The logging macros all use libuv-based I/O, and there was one stray debug statement in task::spawn which was executing before the I/O context was ready. Remove it and add a test to make sure that we can continue to debug this sort of code. Closes #10405
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@ -661,7 +661,6 @@ pub fn spawn_raw(mut opts: TaskOpts, f: ~fn()) {
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};
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new_sched.bootstrap(bootstrap_task);
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debug!("enqueing join_task");
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// Now tell the original scheduler to join with this thread
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// by scheduling a thread-joining task on the original scheduler
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orig_sched_handle.send(TaskFromFriend(join_task));
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22
src/test/run-pass/spawning-with-debug.rs
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22
src/test/run-pass/spawning-with-debug.rs
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@ -0,0 +1,22 @@
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// Copyright 2013 The Rust Project Developers. See the COPYRIGHT
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// file at the top-level directory of this distribution and at
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// http://rust-lang.org/COPYRIGHT.
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//
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// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
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// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
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// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
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// option. This file may not be copied, modified, or distributed
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// except according to those terms.
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// exec-env:RUST_LOG=debug
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// xfail-fast
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// regression test for issue #10405, make sure we don't call debug! too soon.
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use std::task;
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fn main() {
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let mut t = task::task();
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t.sched_mode(task::SingleThreaded);
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t.spawn(|| ());
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}
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