Remove a debug! statement before I/O is ready

The logging macros all use libuv-based I/O, and there was one stray debug
statement in task::spawn which was executing before the I/O context was ready.
Remove it and add a test to make sure that we can continue to debug this sort of
code.

Closes #10405
This commit is contained in:
Alex Crichton 2013-11-10 13:05:36 -08:00
parent 3851f908d1
commit b71d629744
2 changed files with 22 additions and 1 deletions

View File

@ -661,7 +661,6 @@ pub fn spawn_raw(mut opts: TaskOpts, f: ~fn()) {
};
new_sched.bootstrap(bootstrap_task);
debug!("enqueing join_task");
// Now tell the original scheduler to join with this thread
// by scheduling a thread-joining task on the original scheduler
orig_sched_handle.send(TaskFromFriend(join_task));

View File

@ -0,0 +1,22 @@
// Copyright 2013 The Rust Project Developers. See the COPYRIGHT
// file at the top-level directory of this distribution and at
// http://rust-lang.org/COPYRIGHT.
//
// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
// option. This file may not be copied, modified, or distributed
// except according to those terms.
// exec-env:RUST_LOG=debug
// xfail-fast
// regression test for issue #10405, make sure we don't call debug! too soon.
use std::task;
fn main() {
let mut t = task::task();
t.sched_mode(task::SingleThreaded);
t.spawn(|| ());
}