rustc: Don't mark type parameters as exported
This ends up causing the privacy pass to get all confused, and there's nothing inherently exported about them anyway. Closes #14933
This commit is contained in:
parent
01dc27a219
commit
accb442b38
@ -303,7 +303,7 @@ impl<'a> Visitor<()> for EmbargoVisitor<'a> {
|
||||
match ty.node {
|
||||
ast::TyPath(_, _, id) => {
|
||||
match self.tcx.def_map.borrow().get_copy(&id) {
|
||||
def::DefPrimTy(..) => {},
|
||||
def::DefPrimTy(..) | def::DefTyParam(..) => {},
|
||||
def => {
|
||||
let did = def.def_id();
|
||||
if is_local(did) {
|
||||
|
15
src/test/run-pass/issue-14933.rs
Normal file
15
src/test/run-pass/issue-14933.rs
Normal file
@ -0,0 +1,15 @@
|
||||
// Copyright 2014 The Rust Project Developers. See the COPYRIGHT
|
||||
// file at the top-level directory of this distribution and at
|
||||
// http://rust-lang.org/COPYRIGHT.
|
||||
//
|
||||
// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
|
||||
// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
|
||||
// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
|
||||
// option. This file may not be copied, modified, or distributed
|
||||
// except according to those terms.
|
||||
|
||||
#![feature(default_type_params)]
|
||||
|
||||
pub type BigRat<T = int> = T;
|
||||
|
||||
fn main() {}
|
Loading…
x
Reference in New Issue
Block a user