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Remove uses of box_syntax in rustc and tools

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This commit is contained in:
clubby789 2023-02-27 13:07:44 +00:00
parent 386ea3770f
commit a5ba6e025f
4 changed files with 0 additions and 37 deletions
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11
tests/source/expr.rs
View File

@ -3,7 +3,6 @@
// Test expressions
fn foo() -> bool {
let boxed: Box<i32> = box 5;
let referenced = &5 ;
let very_long_variable_name = ( a + first + simple + test );
@ -132,12 +131,6 @@ fn qux() {
}
}
fn issue227() {
{
let handler = box DocumentProgressHandler::new(addr, DocumentProgressTask::DOMContentLoaded);
}
}
fn issue184(source: &str) {
for c in source.chars() {
if index < 'a' {
@ -413,10 +406,6 @@ fn issue2704() {
.concat(&requires1)
.concat(&requires2)
.distinct_total());
let requires = requires.set(box requires0
.concat(&requires1)
.concat(&requires2)
.distinct_total());
let requires = requires.set(requires0
.concat(&requires1)
.concat(&requires2)

6
tests/target/configs/combine_control_expr/false.rs
View File

@ -108,12 +108,6 @@ fn main() {
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbb,
));
// Box
foo(box Bar {
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa,
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbb,
});
// Unary
foo(!bar(
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa,

6
tests/target/configs/combine_control_expr/true.rs
View File

@ -96,12 +96,6 @@ fn main() {
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbb,
));
// Box
foo(box Bar {
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa,
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbb,
});
// Unary
foo(!bar(
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa,

14
tests/target/expr.rs
View File

@ -3,7 +3,6 @@
// Test expressions
fn foo() -> bool {
let boxed: Box<i32> = box 5;
let referenced = &5;
let very_long_variable_name = (a + first + simple + test);
@ -179,13 +178,6 @@ fn qux() {
}
}
fn issue227() {
{
let handler =
box DocumentProgressHandler::new(addr, DocumentProgressTask::DOMContentLoaded);
}
}
fn issue184(source: &str) {
for c in source.chars() {
if index < 'a' {
@ -454,12 +446,6 @@ fn issue2704() {
.concat(&requires2)
.distinct_total(),
);
let requires = requires.set(
box requires0
.concat(&requires1)
.concat(&requires2)
.distinct_total(),
);
let requires = requires.set(
requires0
.concat(&requires1)