Reserve do
as a keyword
Resolves issue #12157. `do` is hereby reinstated as a keyword; no syntax is associated with it though. Along the way, a unit test had to be adapted, since it was using `do` as a method identifier. Breaking changes: - Any code using `do` as an identifier will no longer work.
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@ -492,6 +492,7 @@ declare_special_idents_and_keywords! {
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(53, Typeof, "typeof");
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(54, Unsized, "unsized");
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(55, Yield, "yield");
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(56, Do, "do");
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}
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}
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13
src/test/compile-fail/keyword-do-as-identifier.rs
Normal file
13
src/test/compile-fail/keyword-do-as-identifier.rs
Normal file
@ -0,0 +1,13 @@
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// Copyright 2013 The Rust Project Developers. See the COPYRIGHT
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// file at the top-level directory of this distribution and at
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// http://rust-lang.org/COPYRIGHT.
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//
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// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or
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// http://www.apache.org/licenses/LICENSE-2.0> or the MIT license
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// <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your
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// option. This file may not be copied, modified, or distributed
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// except according to those terms.
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fn main() {
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let do = "bar"; //~ error: ident
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}
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@ -23,7 +23,7 @@ impl Drop for Temporary {
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}
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impl Temporary {
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fn do(&self) -> bool {true}
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fn do_stuff(&self) -> bool {true}
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}
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fn borrow() -> ~Temporary { ~Temporary }
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@ -35,7 +35,7 @@ pub fn main() {
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// This loop's condition
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// should call `Temporary`'s
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// `drop` 6 times.
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while borrow().do() {
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while borrow().do_stuff() {
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i += 1;
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if i > 5 {
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break;
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@ -44,7 +44,7 @@ pub fn main() {
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// This if condition should
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// call it 1 time
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if borrow().do() {
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if borrow().do_stuff() {
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unsafe { assert_eq!(DROPPED, 7) }
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}
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}
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