Rewrite/expansion of slice::split
doc examples.
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@ -691,15 +691,40 @@ pub fn split_at_mut(&mut self, mid: usize) -> (&mut [T], &mut [T]) {
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///
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/// # Examples
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///
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/// Print the slice split by numbers divisible by 3 (i.e. `[10, 40]`,
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/// `[20]`, `[50]`):
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/// ```
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/// let slice = [10, 40, 33, 20];
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/// let mut iter = slice.split(|num| num % 3 == 0);
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///
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/// assert_eq!(iter.next().unwrap(), &[10, 40]);
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/// assert_eq!(iter.next().unwrap(), &[20]);
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/// assert!(iter.next().is_none());
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/// ```
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///
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/// If the first element is matched, an empty slice will be the first item
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/// returned by the iterator. Similarly, if the last element in the slice
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/// is matched, an empty slice will be the last item returned by the
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/// iterator:
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///
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/// ```
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/// let v = [10, 40, 30, 20, 60, 50];
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/// let slice = [10, 40, 33];
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/// let mut iter = slice.split(|num| num % 3 == 0);
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///
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/// for group in v.split(|num| *num % 3 == 0) {
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/// println!("{:?}", group);
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/// }
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/// assert_eq!(iter.next().unwrap(), &[10, 40]);
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/// assert_eq!(iter.next().unwrap(), &[]);
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/// assert!(iter.next().is_none());
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/// ```
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///
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/// If two matched elements are directly adjacent, an empty slice will be
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/// present between them:
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///
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/// ```
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/// let slice = [10, 6, 33, 20];
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/// let mut iter = slice.split(|num| num % 3 == 0);
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///
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/// assert_eq!(iter.next().unwrap(), &[10]);
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/// assert_eq!(iter.next().unwrap(), &[]);
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/// assert_eq!(iter.next().unwrap(), &[20]);
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/// assert!(iter.next().is_none());
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/// ```
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#[stable(feature = "rust1", since = "1.0.0")]
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#[inline]
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