std: Add Vec::from_iter comment
Requested by Niko in #22200 (and is good to have anyway)
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@ -1383,7 +1383,7 @@ fn deref_mut(&mut self) -> &mut [T] { self.as_mut_slice() }
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#[stable(feature = "rust1", since = "1.0.0")]
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impl<T> FromIterator<T> for Vec<T> {
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#[inline]
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fn from_iter<I:Iterator<Item=T>>(iterator: I) -> Vec<T> {
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fn from_iter<I:Iterator<Item=T>>(mut iterator: I) -> Vec<T> {
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let (lower, _) = iterator.size_hint();
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let mut vector = Vec::with_capacity(lower);
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@ -1393,13 +1393,20 @@ fn from_iter<I:Iterator<Item=T>>(iterator: I) -> Vec<T> {
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// vector.push(item);
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// }
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//
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// This equivalent crucially runs the iterator precisely once. The
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// optimization below (eliding bound/growth checks) means that we
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// actually run the iterator twice. To ensure the "moral equivalent" we
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// do a `fuse()` operation to ensure that the iterator continues to
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// return `None` after seeing the first `None`.
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let mut i = iterator.fuse();
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for element in i.by_ref().take(vector.capacity()) {
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// This equivalent crucially runs the iterator precisely once. Below we
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// actually in theory run the iterator twice (one without bounds checks
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// and one with). To achieve the "moral equivalent", we use the `if`
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// statement below to break out early.
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//
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// If the first loop has terminated, then we have one of two conditions.
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//
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// 1. The underlying iterator returned `None`. In this case we are
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// guaranteed that less than `vector.capacity()` elements have been
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// returned, so we break out early.
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// 2. The underlying iterator yielded `vector.capacity()` elements and
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// has not yielded `None` yet. In this case we run the iterator to
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// its end below.
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for element in iterator.by_ref().take(vector.capacity()) {
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let len = vector.len();
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unsafe {
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ptr::write(vector.get_unchecked_mut(len), element);
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@ -1407,8 +1414,10 @@ fn from_iter<I:Iterator<Item=T>>(iterator: I) -> Vec<T> {
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}
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}
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for element in i {
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vector.push(element)
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if vector.len() == vector.capacity() {
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for element in iterator {
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vector.push(element);
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}
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}
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vector
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}
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