Auto merge of #15515 - cardoso:flip-binexpr/lhs-binexpr, r=Veykril
Check if lhs is also a binexpr and use its rhs in flip binexpr assist Closes #15508 From the original PR, flip binexpr assist is not meant to preserve equivalence, so I went with the simplest solution here. I can add some extra checks to keep equivalence, but I think they should go in different specific assists (eg. flip arith op / flip logic op / etc), otherwise this one will get out of hand pretty quickly.
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@ -19,8 +19,19 @@
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// ```
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pub(crate) fn flip_binexpr(acc: &mut Assists, ctx: &AssistContext<'_>) -> Option<()> {
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let expr = ctx.find_node_at_offset::<BinExpr>()?;
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let lhs = expr.lhs()?.syntax().clone();
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let rhs = expr.rhs()?.syntax().clone();
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let lhs = expr.lhs()?.syntax().clone();
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let lhs = if let Some(bin_expr) = BinExpr::cast(lhs.clone()) {
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if bin_expr.op_kind() == expr.op_kind() {
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bin_expr.rhs()?.syntax().clone()
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} else {
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lhs
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}
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} else {
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lhs
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};
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let op_range = expr.op_token()?.text_range();
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// The assist should be applied only if the cursor is on the operator
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let cursor_in_range = op_range.contains_range(ctx.selection_trimmed());
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@ -114,6 +125,24 @@ fn flip_binexpr_works_for_complex_expr() {
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)
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}
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#[test]
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fn flip_binexpr_works_for_lhs_arith() {
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check_assist(
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flip_binexpr,
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r"fn f() { let res = 1 + (2 - 3) +$0 4 + 5; }",
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r"fn f() { let res = 1 + 4 + (2 - 3) + 5; }",
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)
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}
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#[test]
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fn flip_binexpr_works_for_lhs_cmp() {
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check_assist(
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flip_binexpr,
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r"fn f() { let res = 1 + (2 - 3) >$0 4 + 5; }",
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r"fn f() { let res = 4 + 5 < 1 + (2 - 3); }",
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)
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}
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#[test]
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fn flip_binexpr_works_inside_match() {
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check_assist(
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