move the reverse into the iterator
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@ -211,7 +211,7 @@ pub fn minimal_upper_bounds(&self, a: &T, b: &T) -> Vec<&T> {
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// - In the example above, we would reverse to
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// - In the example above, we would reverse to
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// `[z, y, x]` and then pare down to `[z]`.
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// `[z, y, x]` and then pare down to `[z]`.
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// 4. Reverse once more just so that we yield a vector in
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// 4. Reverse once more just so that we yield a vector in
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// increasing order of index. Maybe this is silly.
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// increasing order of index. Not necessary, but why not.
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//
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//
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// I believe this algorithm yields a minimal set. The
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// I believe this algorithm yields a minimal set. The
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// argument is that, after step 2, we know that no element
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// argument is that, after step 2, we know that no element
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@ -224,11 +224,11 @@ pub fn minimal_upper_bounds(&self, a: &T, b: &T) -> Vec<&T> {
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pare_down(&mut candidates, closure); // (2)
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pare_down(&mut candidates, closure); // (2)
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candidates.reverse(); // (3a)
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candidates.reverse(); // (3a)
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pare_down(&mut candidates, closure); // (3b)
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pare_down(&mut candidates, closure); // (3b)
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candidates.reverse(); // (4)
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candidates
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candidates
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});
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});
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lub_indices.into_iter()
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lub_indices.into_iter()
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.rev() // (4)
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.map(|i| &self.elements[i])
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.map(|i| &self.elements[i])
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.collect()
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.collect()
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}
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}
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