borrowck/README.md: Normalize types in examples

This commit is contained in:
Keegan McAllister 2015-02-18 20:46:21 -08:00
parent f051e13238
commit 1597f915c5

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@ -54,7 +54,7 @@ and `*LV` is a pointer dereference. There is no auto-deref or other
niceties. This means that if you have a type like:
```rust
struct S { f: uint }
struct S { f: i32 }
```
and a variable `a: Box<S>`, then the rust expression `a.f` would correspond
@ -63,7 +63,7 @@ to an `LV` of `(*a).f`.
Here is the formal grammar for the types we'll consider:
```text
TY = () | S<'LT...> | Box<TY> | & 'LT MQ TY
TY = i32 | bool | S<'LT...> | Box<TY> | & 'LT MQ TY
MQ = mut | imm
```
@ -83,7 +83,7 @@ SD = struct S<'LT...> { (f: TY)... }
Now, imagine we had a program like this:
```rust
struct Foo { f: uint, g: uint }
struct Foo { f: i32, g: i32 }
...
'a: {
let mut x: Box<Foo> = ...;
@ -508,7 +508,7 @@ of the `&Ty` pointer. In simple cases, this clause is redundant, since
the `LIFETIME()` function will already enforce the required rule:
```rust
fn foo(point: &'a Point) -> &'static f32 {
fn foo(point: &'a Point) -> &'static i32 {
&point.x // Error
}
```
@ -518,7 +518,7 @@ but also by the basic `LIFETIME()` check. However, in more advanced
examples involving multiple nested pointers, clause (1) is needed:
```rust
fn foo(point: &'a &'b mut Point) -> &'b f32 {
fn foo(point: &'a &'b mut Point) -> &'b i32 {
&point.x // Error
}
```
@ -537,7 +537,7 @@ As a final twist, consider the case of two nested *immutable*
pointers, rather than a mutable pointer within an immutable one:
```rust
fn foo(point: &'a &'b Point) -> &'b f32 {
fn foo(point: &'a &'b Point) -> &'b i32 {
&point.x // OK
}
```
@ -559,7 +559,7 @@ create a borrowed pointer that outlives the memory it points at. So
`LIFETIME` prevents a function like this:
```rust
fn get_1<'a>() -> &'a int {
fn get_1<'a>() -> &'a i32 {
let x = 1;
&x
}
@ -579,7 +579,7 @@ mutate it. This distinction is important for type checking functions
like this one:
```rust
fn inc_and_get<'a>(p: &'a mut Point) -> &'a int {
fn inc_and_get<'a>(p: &'a mut Point) -> &'a i32 {
p.x += 1;
&p.x
}
@ -661,8 +661,8 @@ the old name. Here is an example:
```rust
// src/test/compile-fail/borrowck-move-mut-base-ptr.rs
fn foo(t0: &mut int) {
let p: &int = &*t0; // Freezes `*t0`
fn foo(t0: &mut i32) {
let p: &i32 = &*t0; // Freezes `*t0`
let t1 = t0; //~ ERROR cannot move out of `t0`
*t1 = 22; // OK, not a write through `*t0`
}
@ -681,9 +681,9 @@ another path to access the same data, as shown here:
```rust
// src/test/compile-fail/borrowck-mut-borrow-of-mut-base-ptr.rs
fn foo<'a>(mut t0: &'a mut int,
mut t1: &'a mut int) {
let p: &int = &*t0; // Freezes `*t0`
fn foo<'a>(mut t0: &'a mut i32,
mut t1: &'a mut i32) {
let p: &i32 = &*t0; // Freezes `*t0`
let mut t2 = &mut t0; //~ ERROR cannot borrow `t0`
**t2 += 1; // Mutates `*t0`
}
@ -702,9 +702,9 @@ value away to create a new path:
```rust
// src/test/compile-fail/borrowck-swap-mut-base-ptr.rs
fn foo<'a>(mut t0: &'a mut int,
mut t1: &'a mut int) {
let p: &int = &*t0; // Freezes `*t0`
fn foo<'a>(mut t0: &'a mut i32,
mut t1: &'a mut i32) {
let p: &i32 = &*t0; // Freezes `*t0`
swap(&mut t0, &mut t1); //~ ERROR cannot borrow `t0`
*t1 = 22;
}
@ -720,21 +720,21 @@ as shown in the following example:
```rust
// src/test/compile-fail/borrowck-borrow-of-mut-base-ptr.rs
fn foo<'a>(mut t0: &'a mut int,
mut t1: &'a mut int) {
let p: &mut int = &mut *t0; // Claims `*t0`
fn foo<'a>(mut t0: &'a mut i32,
mut t1: &'a mut i32) {
let p: &mut i32 = &mut *t0; // Claims `*t0`
let mut t2 = &t0; //~ ERROR cannot borrow `t0`
let q: &int = &*t2; // Freezes `*t0` but not through `*p`
let q: &i32 = &*t2; // Freezes `*t0` but not through `*p`
*p += 1; // violates type of `*q`
}
```
Here the problem is that `*t0` is claimed by `p`, and hence `p` wants
to be the controlling pointer through which mutation or freezes occur.
But `t2` would -- if it were legal -- have the type `& &mut int`, and
But `t2` would -- if it were legal -- have the type `& &mut i32`, and
hence would be a mutable pointer in an aliasable location, which is
considered frozen (since no one can write to `**t2` as it is not a
unique path). Therefore, we could reasonably create a frozen `&int`
unique path). Therefore, we could reasonably create a frozen `&i32`
pointer pointing at `*t0` that coexists with the mutable pointer `p`,
which is clearly unsound.
@ -743,12 +743,12 @@ particular, if the referent is frozen, there is no harm in it:
```rust
// src/test/run-pass/borrowck-borrow-of-mut-base-ptr-safe.rs
fn foo<'a>(mut t0: &'a mut int,
mut t1: &'a mut int) {
let p: &int = &*t0; // Freezes `*t0`
fn foo<'a>(mut t0: &'a mut i32,
mut t1: &'a mut i32) {
let p: &i32 = &*t0; // Freezes `*t0`
let mut t2 = &t0;
let q: &int = &*t2; // Freezes `*t0`, but that's ok...
let r: &int = &*t0; // ...after all, could do same thing directly.
let q: &i32 = &*t2; // Freezes `*t0`, but that's ok...
let r: &i32 = &*t0; // ...after all, could do same thing directly.
}
```
@ -759,9 +759,9 @@ new alias `t2`, as demonstrated in this test case:
```rust
// src/test/run-pass/borrowck-borrow-mut-base-ptr-in-aliasable-loc.rs
fn foo(t0: & &mut int) {
fn foo(t0: & &mut i32) {
let t1 = t0;
let p: &int = &**t0;
let p: &i32 = &**t0;
**t1 = 22; //~ ERROR cannot assign
}
```
@ -831,8 +831,8 @@ moves/uninitializations of the variable that is being used.
Let's look at a simple example:
```rust
fn foo(a: Box<int>) {
let b: Box<int>; // Gen bit 0.
fn foo(a: Box<i32>) {
let b: Box<i32>; // Gen bit 0.
if cond { // Bits: 0
use(&*a);
@ -846,7 +846,7 @@ fn foo(a: Box<int>) {
use(&*b); // Error.
}
fn use(a: &int) { }
fn use(a: &i32) { }
```
In this example, the variable `b` is created uninitialized. In one
@ -977,8 +977,8 @@ not) the destructor invocation for that path.
A simple example of this is the following:
```rust
struct D { p: int }
impl D { fn new(x: int) -> D { ... }
struct D { p: i32 }
impl D { fn new(x: i32) -> D { ... }
impl Drop for D { ... }
fn foo(a: D, b: D, t: || -> bool) {
@ -1091,7 +1091,7 @@ the elements of an array that has been passed by value, such as
the following:
```rust
fn foo(a: [D; 10], i: uint) -> D {
fn foo(a: [D; 10], i: i32) -> D {
a[i]
}
```
@ -1107,7 +1107,7 @@ all-but-one element of the array. A place where that distinction
would arise is the following:
```rust
fn foo(a: [D; 10], b: [D; 10], i: uint, t: bool) -> D {
fn foo(a: [D; 10], b: [D; 10], i: i32, t: bool) -> D {
if t {
a[i]
} else {
@ -1122,7 +1122,7 @@ fn foo(a: [D; 10], b: [D; 10], i: uint, t: bool) -> D {
There are a number of ways that the trans backend could choose to
compile this (e.g. a `[bool; 10]` array for each such moved array;
or an `Option<uint>` for each moved array). From the viewpoint of the
or an `Option<usize>` for each moved array). From the viewpoint of the
borrow-checker, the important thing is to record what kind of fragment
is implied by the relevant moves.