51 lines
1.8 KiB
Rust
51 lines
1.8 KiB
Rust
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use hir_def::{
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db::DefDatabase,
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resolver::{HasResolver, TypeNs},
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type_ref::TypeRef,
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TraitId,
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};
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use hir_expand::name;
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// FIXME: this is wrong, b/c it can't express `trait T: PartialEq<()>`.
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// We should return a `TraitREf` here.
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fn direct_super_traits(db: &impl DefDatabase, trait_: TraitId) -> Vec<TraitId> {
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let resolver = trait_.resolver(db);
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// returning the iterator directly doesn't easily work because of
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// lifetime problems, but since there usually shouldn't be more than a
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// few direct traits this should be fine (we could even use some kind of
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// SmallVec if performance is a concern)
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db.generic_params(trait_.into())
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.where_predicates
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.iter()
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.filter_map(|pred| match &pred.type_ref {
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TypeRef::Path(p) if p.as_ident() == Some(&name::SELF_TYPE) => pred.bound.as_path(),
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_ => None,
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})
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.filter_map(|path| match resolver.resolve_path_in_type_ns_fully(db, path) {
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Some(TypeNs::TraitId(t)) => Some(t),
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_ => None,
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})
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.collect()
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}
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/// Returns an iterator over the whole super trait hierarchy (including the
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/// trait itself).
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pub(crate) fn all_super_traits(db: &impl DefDatabase, trait_: TraitId) -> Vec<TraitId> {
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// we need to take care a bit here to avoid infinite loops in case of cycles
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// (i.e. if we have `trait A: B; trait B: A;`)
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let mut result = vec![trait_];
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let mut i = 0;
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while i < result.len() {
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let t = result[i];
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// yeah this is quadratic, but trait hierarchies should be flat
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// enough that this doesn't matter
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for tt in direct_super_traits(db, t) {
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if !result.contains(&tt) {
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result.push(tt);
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}
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}
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i += 1;
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}
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result
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}
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