% Checked Uninitialized Memory

Like C, all stack variables in Rust are uninitialized until a value is
explicitly assigned to them. Unlike C, Rust statically prevents you from ever
reading them until you do:

```rust,ignore
fn main() {
    let x: i32;
    println!("{}", x);
}
```

```text
src/main.rs:3:20: 3:21 error: use of possibly uninitialized variable: `x`
src/main.rs:3     println!("{}", x);
                                 ^
```

This is based off of a basic branch analysis: every branch must assign a value
to `x` before it is first used. Interestingly, Rust doesn't require the variable
to be mutable to perform a delayed initialization if every branch assigns
exactly once. However the analysis does not take advantage of constant analysis
or anything like that. So this compiles:

```rust
fn main() {
    let x: i32;

    if true {
        x = 1;
    } else {
        x = 2;
    }

    println!("{}", x);
}
```

but this doesn't:

```rust,ignore
fn main() {
    let x: i32;
    if true {
        x = 1;
    }
    println!("{}", x);
}
```

```text
src/main.rs:6:17: 6:18 error: use of possibly uninitialized variable: `x`
src/main.rs:6   println!("{}", x);
```

while this does:

```rust
fn main() {
    let x: i32;
    if true {
        x = 1;
        println!("{}", x);
    }
    // Don't care that there are branches where it's not initialized
    // since we don't use the value in those branches
}
```

Of course, while the analysis doesn't consider actual values, it does
have a relatively sophisticated understanding of dependencies and control
flow. For instance, this works:

```rust
let x: i32;

loop {
    // Rust doesn't understand that this branch will be taken unconditionally,
    // because it relies on actual values.
    if true {
        // But it does understand that it will only be taken once because
        // we unconditionally break out of it. Therefore `x` doesn't
        // need to be marked as mutable.
        x = 0;
        break;
    }
}
// It also knows that it's impossible to get here without reaching the break.
// And therefore that `x` must be initialized here!
println!("{}", x);
```

If a value is moved out of a variable, that variable becomes logically
uninitialized if the type of the value isn't Copy. That is:

```rust
fn main() {
    let x = 0;
    let y = Box::new(0);
    let z1 = x; // x is still valid because i32 is Copy
    let z2 = y; // y is now logically uninitialized because Box isn't Copy
}
```

However reassigning `y` in this example *would* require `y` to be marked as
mutable, as a Safe Rust program could observe that the value of `y` changed:

```rust
fn main() {
    let mut y = Box::new(0);
    let z = y; // y is now logically uninitialized because Box isn't Copy
    y = Box::new(1); // reinitialize y
}
```

Otherwise it's like `y` is a brand new variable.
